3(q+5)+q^2=q(q+3)+15

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Solution for 3(q+5)+q^2=q(q+3)+15 equation: 



3(q+5)+q^2=q(q+3)+15

We move all terms to the left:

3(q+5)+q^2-(q(q+3)+15)=0

We multiply parentheses

q^2+3q-(q(q+3)+15)+15=0



We calculate terms in parentheses: -(q(q+3)+15), so:

q(q+3)+15

We multiply parentheses

q^2+3q+15

Back to the equation:

-(q^2+3q+15)



We get rid of parentheses

q^2-q^2+3q-3q-15+15=0

We add all the numbers together, and all the variables

=0

q=0/1

q=0

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